Default Value Creating New Value

A common gotcha :slight_smile: You’re using the result of Filter() as is — but this formula always returns a list of elements, even if it’s just one element in the list. What you see is one group for @[New Application], and another for List(@[New Application]). They look the same, yet they are two different things.

You need to use Filter(...).First() whenever you expect just one value.

See:

You should pay extra care to this throughout this doc. Otherwise the issues may pile up until nothing works as expected.

P.S. Instead of the filter, you can simply reference the row itself using @-syntax. Start typing @New Application to select a specific row as a static row reference.


CC @Laurent_Auneau that’s for you too :slight_smile:

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