Is there a way to increment the value of a cell by one using ‘switch if’? I’m trying to make a table that automatically assigns a score to each row depending on multiple factors across columns. Here are the specifics:
- The purpose of the table is to track the value of SEO keywords based on multiple factors (inspired by Ubersuggest’s ranking system)
- Each keyword gets its own row
- The fields for each column are: keyword, search volume, cost per click, paid difficulty, SEO difficulty usage, notes, and score
Every time a value of ‘true’ is returned on one of the following conditions, I want to add 1 to the value of that row’s ‘score’:
- thisRow.SEO Difficulty < 40
- thisRow.Paid Difficulty < 40
- thisRow.Cost per Click > 0
- thisRow.Cost per Click > 5
- thisRow.Search Volume > 10
- thisRow.Search Volume > 50
- thisRow.Search Volume > 100
- thisRow.SEO Difficulty < 40 && Cost per Click > 5
Thank you in advance for your help!
Hi Shaina,
Switchif() is not going to work in this situation - it stops executing when it gets to the first expression that results in true.
I would suggest to use runActions() to evaluate each of those expression in series. If the If() expression is true, add one to a column that you use as a counter.
See the last example on the page below:
Regards
Piet
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Thank you for your reply! That makes sense. Is there any way to accomplish this without requiring a button for each row?
Yes! I would recommend the non-button route
What you should likely do is create a list of true/false values, then filter that list to find values that are TRUE, then count your new list
So:
- List(thisRow.status = Done, thisRow.amount>40, thisRow.date = today()).filter(currentValue=true).count()
That should essentially return a count of the true values within your list, aka assigning one point per true value
Simply input all your statements into the List() formula rather than my fake ones
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Very clever idea!
I was stuck on getting it done using runaction(), which forces me into a button.
Brilliant! That worked perfectly. Thank you!
Hello @Shaina_Nacion ,
I don’t know how your information is collected and how it finds its way into your document (or table), but there is an alternative very easy solution:
The formula in “score” is very simple:
thisRow.[SEO Difficulty <40]+thisRow.[Paid Difficulty <40]+thisRow.[Cost per Click >0]+thisRow.[Cost per Click > 5]
This is probably not how I would organize my data, but with the limited knowledge of your project this might work for you.
Greetings, Joost
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