Great question here and it’s not necessarily an intuitive formula that can make this work, but @Pch has the right idea. Using ListCombine()
and Filter()
will make this list possible.
ListCombine([Column 1], [Column 2], [Column 3]).Filter(CurrentValue.IsNotBlank())
I think that should work.
List()
can create (One, Two, [Three, Four, Five]) where [Three, Four, Five] is considered 1 item.
ListCombine()
flattens it and makes this (One, Two, Three, Four, Five) and is considered 5 items.