ACTIVATE with Page as the object

1

In the Coda Reference it says that you can use a PAGE as input for the ACTIVATE action. However, there is no syntax and I’ve tried everything I can think of and all I get are errors. Can someone please tell me the SYNTAX for ACTIVATE(page). I’ve tried Activate(“Page”), Activate(@Page), and various other ways. If I type @and start typing the page name I see all the tables, rows, etc that start with those letters but PAGES never show up as they do when I’m just editing a page itself and type @Page Name.

2

I too was frustrated by the inaccuracy of the documentation for Activate(), it only opens ROWS.

But I have overcome the issue for PAGES using the following action

OpenWindow("https://coda.io/d/Xxxxxxxxxx_dZf94eUD0KC/ZZZZZZ_suqV8#_lu8Jb")

Where the string is the URL of the page you want to open.

(thanks to @Nick_HE for this suggestion)

respect
max

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3

Thanks for posting about the difficulty with the syntax for Activate @Susan_M_Davis! As @Agile_Dynamics said, you would use a row with the Activate function:

=Activate(thisRow)

A few places this formula is discussed are here and here.

4

Right. But the Coda formula reference documentation says it works with PAGES. That needs to be corrected if that isn’t true.

1 Like
5

Yup this is something we need to change!

6

I struggled with this too today. It appears that the formula helper has not been updated yet.